Old Christianburg, Shelby County, Kentucky, United States
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- Old Christianburg
- Unincorporated Populated Place
- 38.281459138° 16' 53.3"N-85.084953885° 05' 05.8"W
- Christianburg 0.8 mi. W
- Bagdad 2 mi. SE
- Pleasureville (Henry County) 4.7 mi. N
- Eminence (Henry County) 8 mi. NW
- Shelbyville 8.9 mi. SW
- New Castle (Henry County) 11.5 mi. NW
- Gill 3.9 mi. N
- Dutch Tract (Henry County) 4.5 mi. N
- Monfort (Henry County) 5.4 mi. N
- Beech Ridge 5.5 mi. SE
- Magruder 5.6 mi. NW
- Banta - Bonta (Henry County) 5.7 mi. N
- Sudduth (Franklin County) 6.5 mi. E
- Adcock (Henry County) 6.6 mi. NE
- Willhite (Henry County) 7.3 mi. N
- Eminence (Henry County) 7.5 mi. NW
- Bailey (Franklin County) 7.8 mi. NE
- Hutcherson (Franklin County) 8 mi. E
- 263 m
- 293509863
- Updated Jan 25, 2016